What is the answer to 9^{5x+2}=(1/3)^{11-x} ?

The answer to 9^{5x+2}=(1/3)^{11-x} is x=-5/3

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9^{5x+2}=(1/3)^{11-x}

9^{5 x + 2} = (\frac{1}{3})^{11 - x}

x = - \frac{5}{3}

Decimal Notation

x = - 1.66666 \dots

Solution steps

9^{5 x + 2} = (\frac{1}{3})^{11 - x}

Apply exponent rules

2 (5 x + 2) = - (11 - x)

Solve

2 (5 x + 2) = - (11 - x) : x = - \frac{5}{3}

x = - \frac{5}{3}

2^{6 l o g_{4} (x)} = 8

2^{2 x} \cdot 2 = 3^{x} \cdot 3^{5}

10 e^{2 n - 10} - 5 = 73

e^{e^{x}} = 3

4 9^{x} = \frac{1}{7}

What is the answer to 9^{5x+2}=(1/3)^{11-x} ?
The answer to 9^{5x+2}=(1/3)^{11-x} is x=-5/3
Solve for x: 9^{5x+2}=(1/3)^{11-x}
The solution is x=-5/3