What are the solutions to the equation 2(x+3)x=5 ?

The solutions to the equation 2(x+3)x=5 are x=(-3+sqrt(19))/2 ,x=-(3+sqrt(19))/2

Find the zeros of 2(x+3)x=5

The zeros of 2(x+3)x=5 are x=(-3+sqrt(19))/2 ,x=-(3+sqrt(19))/2

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2 (x + 3) x = 5

x = \frac{- 3 + 19}{2}, x = - \frac{3 + 19}{2}

Solution steps

2 (x + 3) x = 5

Expand

2 (x + 3) x : 2 x^{2} + 6 x

2 x^{2} + 6 x = 5

Move

5

to the left side

2 x^{2} + 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 5) = 219

x_{1, 2} = \frac{- 6 \pm 2 19}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 2 19}{2 \cdot 2}, x_{2} = \frac{- 6 - 2 19}{2 \cdot 2}

x = \frac{- 6 + 2 19}{2 \cdot 2} : \frac{- 3 + 19}{2}

x = \frac{- 6 - 2 19}{2 \cdot 2} : - \frac{3 + 19}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 19}{2}, x = - \frac{3 + 19}{2}

∣ 8 x + 3 ∣ > 14

15 - \frac{1}{6} n = \frac{1}{6} n - 1

(\frac{2 m ^{4}}{m ^{2}})^{- 4}

∣ x - 5 ∣ = 8

6 x + 3 \leq 15

What are the solutions to the equation 2(x+3)x=5 ?
The solutions to the equation 2(x+3)x=5 are x=(-3+sqrt(19))/2 ,x=-(3+sqrt(19))/2
Find the zeros of 2(x+3)x=5
The zeros of 2(x+3)x=5 are x=(-3+sqrt(19))/2 ,x=-(3+sqrt(19))/2