What is the answer to e^{2x}+2sqrt(e^{2x+1)}=1-e ?

The answer to e^{2x}+2sqrt(e^{2x+1)}=1-e is No Solution for x\in\mathbb{R}

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e^{2x}+2sqrt(e^{2x+1)}=1-e

e^{2 x} + 2 e^{2 x + 1} = 1 - e

No Solution for x \in R

Solution steps

e^{2 x} + 2 e^{2 x + 1} = 1 - e

Apply exponent rules

e^{2 x} + 2 e^{2 x} e^{1} = 1 - e

Rewrite the equation with

e^{2 x} = u

u + 2 u e^{1} = 1 - e

Solve

u + 2 u e^{1} = 1 - e :

No Solution for

u \in R

No Solution for x \in R

1 6^{x - 1} = 2^{3 x + 2}

1 0^{\frac{2 z}{3}} = 15

(\frac{1}{5})^{2 x} = 625

8 1^{4 x - 1} = 9^{x + 5}

2^{x} \cdot 8^{1 - x} = \frac{1}{4}

What is the answer to e^{2x}+2sqrt(e^{2x+1)}=1-e ?
The answer to e^{2x}+2sqrt(e^{2x+1)}=1-e is No Solution for x\in\mathbb{R}