What is the answer to 3^{5x}=7^{1-5x} ?

The answer to 3^{5x}=7^{1-5x} is x=(ln(7))/(5ln(21))

Solve for x: 3^{5x}=7^{1-5x}

The solution is x=(ln(7))/(5ln(21))

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3^{5 x} = 7^{1 - 5 x}

x = \frac{ln ( 7 )}{5 ln ( 21 )}

Solution steps

3^{5 x} = 7^{1 - 5 x}

Apply exponent rules

5 x ln (3) = (1 - 5 x) ln (7)

Solve

5 x ln (3) = (1 - 5 x) ln (7) : x = \frac{ln ( 7 )}{5 ln ( 21 )}

x = \frac{ln ( 7 )}{5 ln ( 21 )}

e^{t} = 1 + 6 e^{- t}

e^{5 x} = 5 e^{x}

3^{x} = 100

3^{x - 5} = 2 7^{1 - x}

x^{l o g_{10} (4 x)} - 17 = 239

What is the answer to 3^{5x}=7^{1-5x} ?
The answer to 3^{5x}=7^{1-5x} is x=(ln(7))/(5ln(21))
Solve for x: 3^{5x}=7^{1-5x}
The solution is x=(ln(7))/(5ln(21))