What is the answer to 3^{(x-4)}=7 ?

The answer to 3^{(x-4)}=7 is x=(ln(7))/(ln(3))+4

Solve for x: 3^{(x-4)}=7

The solution is x=(ln(7))/(ln(3))+4

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3^{(x - 4)} = 7

x = \frac{ln ( 7 )}{ln ( 3 )} + 4

Solution steps

3^{(x - 4)} = 7

Apply exponent rules

(x - 4) ln (3) = ln (7)

Solve

(x - 4) ln (3) = ln (7) : x = \frac{ln ( 7 )}{ln ( 3 )} + 4

x = \frac{ln ( 7 )}{ln ( 3 )} + 4

(\frac{1}{4})^{x + 1} = 32

2 \cdot e^{- 6 w} = 95

3^{x} = 24

\frac{4 ^{6}}{4 ^{x}} = 4^{0}

2^{2 y} \cdot 2^{2 y - 12} = 16

What is the answer to 3^{(x-4)}=7 ?
The answer to 3^{(x-4)}=7 is x=(ln(7))/(ln(3))+4
Solve for x: 3^{(x-4)}=7
The solution is x=(ln(7))/(ln(3))+4