What is the answer to 8(8^{2x})-65(8^x)+8=0 ?

The answer to 8(8^{2x})-65(8^x)+8=0 is x=1,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8(8^{2x})-65(8^x)+8=0

8 (8^{2 x}) - 65 (8^{x}) + 8 = 0

x = 1, x = - 1

Solution steps

8 (8^{2 x}) - 65 (8^{x}) + 8 = 0

Apply exponent rules

(8^{x})^{2} \cdot 8^{1} - 65 \cdot 8^{x} + 8 = 0

Rewrite the equation with

8^{x} = u

(u)^{2} \cdot 8^{1} - 65 u + 8 = 0

Solve

u^{2} \cdot 8^{1} - 65 u + 8 = 0 : u = 8, u = \frac{1}{8}

u = 8, u = \frac{1}{8}

Substitute back

u = 8^{x},

solve for

x

Solve

8^{x} = 8 : x = 1

Solve

8^{x} = \frac{1}{8} : x = - 1

x = 1, x = - 1

(\frac{1}{25})^{x - 1} = 55

1 = e^{2 x - 3} - 5

e^{2 x + 3} = 27

2^{x - 2} = 8

What is the answer to 8(8^{2x})-65(8^x)+8=0 ?
The answer to 8(8^{2x})-65(8^x)+8=0 is x=1,x=-1
Solve for x: 8(8^{2x})-65(8^x)+8=0
The solution is x=1,x=-1