What is the answer to 2^{4^{2x-1}}=4^{2^{x-1}} ?

The answer to 2^{4^{2x-1}}=4^{2^{x-1}} is x= 2/3

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2^{4^{2x-1}}=4^{2^{x-1}}

2^{4^{2 x - 1}} = 4^{2^{x - 1}}

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

2^{4^{2 x - 1}} = 4^{2^{x - 1}}

Apply exponent rules

2 (2 x - 1) = x

Solve

2 (2 x - 1) = x : x = \frac{2}{3}

x = \frac{2}{3}

2^{x} + 2^{- x} = 2

5 e^{3 x - 4} = 25

32 \cdot e^{- 0.25 x} = 4

- 14 + 3 e^{x} = 11

5 \cdot 2^{- 3 t} = 45

What is the answer to 2^{4^{2x-1}}=4^{2^{x-1}} ?
The answer to 2^{4^{2x-1}}=4^{2^{x-1}} is x= 2/3
Solve for x: 2^{4^{2x-1}}=4^{2^{x-1}}
The solution is x= 2/3