What is the answer to 0.7937^x=(1.25)/(10) ?

The answer to 0.7937^x=(1.25)/(10) is x=(ln(\frac{1.25)/(10))}{ln(0.7937)}

Solve for x: 0.7937^x=(1.25)/(10)

The solution is x=(ln(\frac{1.25)/(10))}{ln(0.7937)}

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0.793 7^{x} = \frac{1.25}{10}

x = \frac{ln ( \frac{1.25}{10} )}{ln ( 0.7937 )}

Solution steps

0.793 7^{x} = \frac{1.25}{10}

Apply exponent rules

x ln (0.7937) = ln (\frac{1.25}{10})

Solve

x ln (0.7937) = ln (\frac{1.25}{10}) : x = \frac{ln ( \frac{1.25}{10} )}{ln ( 0.7937 )}

x = \frac{ln ( \frac{1.25}{10} )}{ln ( 0.7937 )}

x, 4 = y^{2 x}

3^{4 x + 5} = 8 1^{- \frac{3}{4}}

4^{2 x} - 2^{2 x + 1} = 35

\frac{2 5 ^{x} + 125}{6} = 5^{x + 1}

1 0^{x} = 200

What is the answer to 0.7937^x=(1.25)/(10) ?
The answer to 0.7937^x=(1.25)/(10) is x=(ln(\frac{1.25)/(10))}{ln(0.7937)}
Solve for x: 0.7937^x=(1.25)/(10)
The solution is x=(ln(\frac{1.25)/(10))}{ln(0.7937)}