What is the answer to 8(2^{2x})-65(2^x)+8=0 ?

The answer to 8(2^{2x})-65(2^x)+8=0 is x=3,x=-3

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8(2^{2x})-65(2^x)+8=0

8 (2^{2 x}) - 65 (2^{x}) + 8 = 0

x = 3, x = - 3

Solution steps

8 (2^{2 x}) - 65 (2^{x}) + 8 = 0

Apply exponent rules

8 (2^{x})^{2} - 65 \cdot 2^{x} + 8 = 0

Rewrite the equation with

2^{x} = u

8 (u)^{2} - 65 u + 8 = 0

Solve

8 u^{2} - 65 u + 8 = 0 : u = 8, u = \frac{1}{8}

u = 8, u = \frac{1}{8}

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 8 : x = 3

Solve

2^{x} = \frac{1}{8} : x = - 3

x = 3, x = - 3

1000000 = 2^{n} \cdot 5^{n}

6 4^{x} - 8 = 7 (4^{x} - 2)

3^{x} = x^{2}

5 \cdot 1 0^{\frac{z}{4}} = 32

3^{2 x + 1} + 3 = 10 \cdot 3^{x}

What is the answer to 8(2^{2x})-65(2^x)+8=0 ?
The answer to 8(2^{2x})-65(2^x)+8=0 is x=3,x=-3
Solve for x: 8(2^{2x})-65(2^x)+8=0
The solution is x=3,x=-3