What is the answer to 3^{x+2}=7^x ?

The answer to 3^{x+2}=7^x is x=(2ln(3))/(ln(7)-ln(3))

Solve for x: 3^{x+2}=7^x

The solution is x=(2ln(3))/(ln(7)-ln(3))

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3^{x + 2} = 7^{x}

x = \frac{2 ln ( 3 )}{ln ( 7 ) - ln ( 3 )}

Solution steps

3^{x + 2} = 7^{x}

Apply exponent rules

(x + 2) ln (3) = x ln (7)

Solve

(x + 2) ln (3) = x ln (7) : x = \frac{2 ln ( 3 )}{ln ( 7 ) - ln ( 3 )}

x = \frac{2 ln ( 3 )}{ln ( 7 ) - ln ( 3 )}

e^{x^{2}} = 312

(\frac{1}{3})^{x} = 3

4^{2 x - 7} = 102 4^{x + 1}

e^{0.5 x} = 5 - 5 x

e^{- 2 x} = 5

What is the answer to 3^{x+2}=7^x ?
The answer to 3^{x+2}=7^x is x=(2ln(3))/(ln(7)-ln(3))
Solve for x: 3^{x+2}=7^x
The solution is x=(2ln(3))/(ln(7)-ln(3))