What is the answer to 8^{(x+1)}+8^{(1-x)}=20 ?

The answer to 8^{(x+1)}+8^{(1-x)}=20 is x= 1/3 ,x=-1/3

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8^{(x+1)}+8^{(1-x)}=20

8^{(x + 1)} + 8^{(1 - x)} = 20

x = \frac{1}{3}, x = - \frac{1}{3}

Solution steps

8^{(x + 1)} + 8^{(1 - x)} = 20

Apply exponent rules

8^{x} \cdot 8^{1} + (8^{x})^{- 1} \cdot 8^{1} = 20

Rewrite the equation with

8^{x} = u

u \cdot 8^{1} + (u)^{- 1} \cdot 8^{1} = 20

Solve

u \cdot 8^{1} + u^{- 1} \cdot 8^{1} = 20 : u = 2, u = \frac{1}{2}

u = 2, u = \frac{1}{2}

Substitute back

u = 8^{x},

solve for

x

Solve

8^{x} = 2 : x = \frac{1}{3}

Solve

8^{x} = \frac{1}{2} : x = - \frac{1}{3}

x = \frac{1}{3}, x = - \frac{1}{3}

1 6^{x} = 2

12 e^{- 3 x} = 2 e^{x}

x, y = e^{- x}

0 = 4 e^{4 x} + 16 x e^{4 x}

(2)^{3 x} = \frac{1}{8}

What is the answer to 8^{(x+1)}+8^{(1-x)}=20 ?
The answer to 8^{(x+1)}+8^{(1-x)}=20 is x= 1/3 ,x=-1/3
Solve for x: 8^{(x+1)}+8^{(1-x)}=20
The solution is x= 1/3 ,x=-1/3