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Popular >

solvefor x,y=5e^{2x}

Solution

solve for

x, y = 5 e^{2 x}

Solution

x = \frac{ln ( \frac{y}{5} )}{2}

Solution steps

y = 5 e^{2 x}

Switch sides

5 e^{2 x} = y

Divide both sides by

5

e^{2 x} = \frac{y}{5}

Apply exponent rules

2 x = ln (\frac{y}{5})

Solve

2 x = ln (\frac{y}{5}) : x = \frac{ln ( \frac{y}{5} )}{2}

x = \frac{ln ( \frac{y}{5} )}{2}

Popular Examples

cube root of 25^x}=\sqrt{5

e^{- l n (x)} = 3

2 5^{x} - 5^{x} = 12

2^{2x}+5*2^x-14=0

2^{2 x} + 5 \cdot 2^{x} - 14 = 0

9^{x} + 20 = 3^{x + 2}

Frequently Asked Questions (FAQ)

What is the answer to solvefor x,y=5e^{2x} ?
The answer to solvefor x,y=5e^{2x} is x=(ln(y/5))/2