What is the answer to 10^{2x^2+2x}=100^{-6x+8} ?

The answer to 10^{2x^2+2x}=100^{-6x+8} is x=1,x=-8

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10^{2x^2+2x}=100^{-6x+8}

1 0^{2 x^{2} + 2 x} = 10 0^{- 6 x + 8}

x = 1, x = - 8

Solution steps

1 0^{2 x^{2} + 2 x} = 10 0^{- 6 x + 8}

Apply exponent rules

2 x^{2} + 2 x = 2 (- 6 x + 8)

Solve

2 x^{2} + 2 x = 2 (- 6 x + 8) : x = 1, x = - 8

x = 1, x = - 8

(2 e)^{(x^{2} - 2)} = 4

- 4 \cdot 3^{6 w} = - 1750

x, e = e^{x y}

(\frac{1}{4})^{x} = 64

\frac{( 2 ^{x} - 2 ^{- x} )}{3} = 4

What is the answer to 10^{2x^2+2x}=100^{-6x+8} ?
The answer to 10^{2x^2+2x}=100^{-6x+8} is x=1,x=-8
Solve for x: 10^{2x^2+2x}=100^{-6x+8}
The solution is x=1,x=-8