What is the answer to sqrt(3^{2x-1)}=9^{x-2} ?

The answer to sqrt(3^{2x-1)}=9^{x-2} is x= 7/2

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sqrt(3^{2x-1)}=9^{x-2}

3^{2 x - 1} = 9^{x - 2}

x = \frac{7}{2}

Decimal Notation

x = 3.5

Solution steps

3^{2 x - 1} = 9^{x - 2}

Apply exponent rules

(2 x - 1) \frac{1}{2} = 2 (x - 2)

Solve

(2 x - 1) \frac{1}{2} = 2 (x - 2) : x = \frac{7}{2}

x = \frac{7}{2}

133.9 = \frac{133.9}{1 + 2 e ^{- x}}

3 e^{- 5 x - 8} - 4 = 9

5^{x - 2} - 5^{x} + 5^{x - 1} = 505

2^{x} + 2^{x + 2} = 40

What is the answer to sqrt(3^{2x-1)}=9^{x-2} ?
The answer to sqrt(3^{2x-1)}=9^{x-2} is x= 7/2
Solve for x: sqrt(3^{2x-1)}=9^{x-2}
The solution is x= 7/2