What is the answer to 4^x=6^{x+2} ?

The answer to 4^x=6^{x+2} is x=(2ln(6))/(ln(2/3))

Solve for x: 4^x=6^{x+2}

The solution is x=(2ln(6))/(ln(2/3))

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4^{x} = 6^{x + 2}

x = \frac{2 ln ( 6 )}{ln ( \frac{2}{3} )}

Decimal Notation

x = - 8.83804 \dots

Solution steps

4^{x} = 6^{x + 2}

Apply exponent rules

x ln (4) = (x + 2) ln (6)

Solve

x ln (4) = (x + 2) ln (6) : x = \frac{2 ln ( 6 )}{ln ( \frac{2}{3} )}

x = \frac{2 ln ( 6 )}{ln ( \frac{2}{3} )}

3 6^{x} = 6

2^{x - 1} + 2^{x} = 48

(7)^{6 x} = 4 9^{x - 6}

4^{x - 1} = 2^{x} + 48

1 5^{4 a} = 8 1^{a + 2}

What is the answer to 4^x=6^{x+2} ?
The answer to 4^x=6^{x+2} is x=(2ln(6))/(ln(2/3))
Solve for x: 4^x=6^{x+2}
The solution is x=(2ln(6))/(ln(2/3))