What is the answer to 4^x=6^{1-x} ?

The answer to 4^x=6^{1-x} is x=(ln(6))/(ln(24))

Solve for x: 4^x=6^{1-x}

The solution is x=(ln(6))/(ln(24))

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4^{x} = 6^{1 - x}

x = \frac{ln ( 6 )}{ln ( 24 )}

Decimal Notation

x = 0.56379 \dots

Solution steps

4^{x} = 6^{1 - x}

Apply exponent rules

x ln (4) = (1 - x) ln (6)

Solve

x ln (4) = (1 - x) ln (6) : x = \frac{ln ( 6 )}{ln ( 24 )}

x = \frac{ln ( 6 )}{ln ( 24 )}

5^{3 x + 2} + 3 \cdot 5^{6 x + 2} - 100 = 0

3^{5 x + 2} = 21

6^{x} = 4

2^{x + 2} - 4^{x + 1} = - 960

5 = 3^{x}

What is the answer to 4^x=6^{1-x} ?
The answer to 4^x=6^{1-x} is x=(ln(6))/(ln(24))
Solve for x: 4^x=6^{1-x}
The solution is x=(ln(6))/(ln(24))