What is the answer to 2^{x+2}+3*2^{x-1}=22 ?

The answer to 2^{x+2}+3*2^{x-1}=22 is x=2

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2^{x+2}+3*2^{x-1}=22

2^{x + 2} + 3 \cdot 2^{x - 1} = 22

x = 2

Solution steps

2^{x + 2} + 3 \cdot 2^{x - 1} = 22

Factor

2^{x + 2} + 3 \cdot 2^{x - 1} : 11 \cdot 2^{x - 1}

11 \cdot 2^{x - 1} = 22

Divide both sides by

11

2^{x - 1} = 2

Apply exponent rules

x - 1 = 1

Solve

x - 1 = 1 : x = 2

x = 2

2^{2 x - 3} = 8

1 0^{x} = 7

3^{x + 2} + 3^{x} + 3^{x - 2} = 91

2^{x^{2} + 2 x + 1} = 3

3^{2 x} - 30 (3^{x}) + 81 = 0

What is the answer to 2^{x+2}+3*2^{x-1}=22 ?
The answer to 2^{x+2}+3*2^{x-1}=22 is x=2
Solve for x: 2^{x+2}+3*2^{x-1}=22
The solution is x=2