What is the answer to sqrt(8^{3-x)}=4*2^{1-2x} ?

The answer to sqrt(8^{3-x)}=4*2^{1-2x} is x=-3

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sqrt(8^{3-x)}=4*2^{1-2x}

8^{3 - x} = 4 \cdot 2^{1 - 2 x}

x = - 3

Solution steps

8^{3 - x} = 4 \cdot 2^{1 - 2 x}

Apply exponent rules

\frac{3}{2} (3 - x) = - 2 x + 3

Solve

\frac{3}{2} (3 - x) = - 2 x + 3 : x = - 3

x = - 3

\frac{1}{49} = 7^{n}

2 5^{x} - 6 \cdot 5^{x} - 16 = 0

x^{4} = 4^{x}

1 1^{2 x^{2} - 5 x + 2} = 1

(\frac{1}{125})^{x} = 25

What is the answer to sqrt(8^{3-x)}=4*2^{1-2x} ?
The answer to sqrt(8^{3-x)}=4*2^{1-2x} is x=-3
Solve for x: sqrt(8^{3-x)}=4*2^{1-2x}
The solution is x=-3