What is the answer to 2^{3x+7}-9=17 ?

The answer to 2^{3x+7}-9=17 is x=(ln(13/64))/(3ln(2))

Solve for x: 2^{3x+7}-9=17

The solution is x=(ln(13/64))/(3ln(2))

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2^{3 x + 7} - 9 = 17

x = \frac{ln ( \frac{13}{64} )}{3 ln ( 2 )}

Decimal Notation

x = - 0.76652 \dots

Solution steps

2^{3 x + 7} - 9 = 17

Move

9

to the right side

2^{3 x + 7} = 26

Apply exponent rules

(3 x + 7) ln (2) = ln (26)

Solve

(3 x + 7) ln (2) = ln (26) : x = \frac{ln ( \frac{13}{64} )}{3 ln ( 2 )}

x = \frac{ln ( \frac{13}{64} )}{3 ln ( 2 )}

x^{x^{5}} = 5

6^{x} = 81 \cdot 2^{x}

3^{2} 9^{x - 2} = 2 7^{x + 1}

e^{x} + e^{- x} = 8

2 - 3^{- x} = - 1

What is the answer to 2^{3x+7}-9=17 ?
The answer to 2^{3x+7}-9=17 is x=(ln(13/64))/(3ln(2))
Solve for x: 2^{3x+7}-9=17
The solution is x=(ln(13/64))/(3ln(2))