What is the answer to 5^{2x}-26*5^x+25=0 ?

The answer to 5^{2x}-26*5^x+25=0 is x=2,x=0

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5^{2x}-26*5^x+25=0

5^{2 x} - 26 \cdot 5^{x} + 25 = 0

x = 2, x = 0

Solution steps

5^{2 x} - 26 \cdot 5^{x} + 25 = 0

Apply exponent rules

(5^{x})^{2} - 26 \cdot 5^{x} + 25 = 0

Rewrite the equation with

5^{x} = u

(u)^{2} - 26 u + 25 = 0

Solve

u^{2} - 26 u + 25 = 0 : u = 25, u = 1

u = 25, u = 1

Substitute back

u = 5^{x},

solve for

x

Solve

5^{x} = 25 : x = 2

Solve

5^{x} = 1 : x = 0

x = 2, x = 0

9^{x} - 3^{x} = 72

2^{3 x} = 91

e^{x} x = 0

\frac{y e ^{y} - 9 y}{e ^{y}} = 0

3 2^{x} = \frac{1}{4}

What is the answer to 5^{2x}-26*5^x+25=0 ?
The answer to 5^{2x}-26*5^x+25=0 is x=2,x=0
Solve for x: 5^{2x}-26*5^x+25=0
The solution is x=2,x=0