What is the answer to 5^{x+1}=2(3^{2x}) ?

The answer to 5^{x+1}=2(3^{2x}) is x=(ln(5)-ln(2))/(2ln(3)-ln(5))

Solve for x: 5^{x+1}=2(3^{2x})

The solution is x=(ln(5)-ln(2))/(2ln(3)-ln(5))

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5^{x + 1} = 2 (3^{2 x})

x = \frac{ln ( 5 ) - ln ( 2 )}{2 ln ( 3 ) - ln ( 5 )}

Solution steps

5^{x + 1} = 2 (3^{2 x})

Apply exponent rules

(x + 1) ln (5) = ln (2) + 2 x ln (3)

Solve

(x + 1) ln (5) = ln (2) + 2 x ln (3) : x = \frac{ln ( 5 ) - ln ( 2 )}{2 ln ( 3 ) - ln ( 5 )}

x = \frac{ln ( 5 ) - ln ( 2 )}{2 ln ( 3 ) - ln ( 5 )}

4^{2 p} = 4^{- 2 p - 1}

2^{3 x + 1} = 4

x, e^{2 x} - e^{x} = 0

3^{5 + 4 x} = 9^{x}

y, x = 6^{3 + 2 y}

What is the answer to 5^{x+1}=2(3^{2x}) ?
The answer to 5^{x+1}=2(3^{2x}) is x=(ln(5)-ln(2))/(2ln(3)-ln(5))
Solve for x: 5^{x+1}=2(3^{2x})
The solution is x=(ln(5)-ln(2))/(2ln(3)-ln(5))