What is the answer to 4^{x+2}=12 ?

The answer to 4^{x+2}=12 is x=(ln(12))/(2ln(2))-2

Solve for x: 4^{x+2}=12

The solution is x=(ln(12))/(2ln(2))-2

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4^{x + 2} = 12

x = \frac{ln ( 12 )}{2 ln ( 2 )} - 2

Decimal Notation

x = - 0.20751 \dots

Solution steps

4^{x + 2} = 12

Apply exponent rules

(x + 2) ln (4) = ln (12)

Solve

(x + 2) ln (4) = ln (12) : x = \frac{ln ( 12 )}{2 ln ( 2 )} - 2

x = \frac{ln ( 12 )}{2 ln ( 2 )} - 2

5^{9 x + 5} = 2

y, x = e^{y} - e^{- y}

6 \cdot 2^{\frac{x}{4}} = 222

e^{2 x} + e^{x} = 0

6^{4 x - 9} = (\frac{1}{36})^{x - 4}

What is the answer to 4^{x+2}=12 ?
The answer to 4^{x+2}=12 is x=(ln(12))/(2ln(2))-2
Solve for x: 4^{x+2}=12
The solution is x=(ln(12))/(2ln(2))-2