What is the answer to 3^{x^2+x}=sqrt(3) ?

The answer to 3^{x^2+x}=sqrt(3) is x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2

Solve for x: 3^{x^2+x}=sqrt(3)

The solution is x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2

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3^{x^{2} + x} = 3

x = \frac{- 1 + 3}{2}, x = - \frac{1 + 3}{2}

Decimal Notation

x = 0.36602 \dots, x = - 1.36602 \dots

Solution steps

3^{x^{2} + x} = 3

Apply exponent rules

x^{2} + x = \frac{1}{2}

Solve

x^{2} + x = \frac{1}{2} : x = \frac{- 1 + 3}{2}, x = - \frac{1 + 3}{2}

x = \frac{- 1 + 3}{2}, x = - \frac{1 + 3}{2}

e^{2 t - 1} - 3 = 0

e^{- 0.3 t} = 27

e^{y} = 75

e^{- x} = 3

3^{x - 3} = 5

What is the answer to 3^{x^2+x}=sqrt(3) ?
The answer to 3^{x^2+x}=sqrt(3) is x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2
Solve for x: 3^{x^2+x}=sqrt(3)
The solution is x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2