What is the answer to (2^x)/(2^x)=2^{-2x} ?

The answer to (2^x)/(2^x)=2^{-2x} is x=0

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(2^x)/(2^x)=2^{-2x}

\frac{2 ^{x}}{2 ^{x}} = 2^{- 2 x}

x = 0

Solution steps

\frac{2 ^{x}}{2 ^{x}} = 2^{- 2 x}

Apply exponent rules

0 = - 2 x

Solve

0 = - 2 x : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

8 1^{5} = 3^{x}

3^{2 x} - 3^{x + 1} + 2 = 0

2^{3 x + 4} = 4^{2 x + 3}

e^{3 x} = 9

4 = e^{x}

What is the answer to (2^x)/(2^x)=2^{-2x} ?
The answer to (2^x)/(2^x)=2^{-2x} is x=0
Solve for x: (2^x)/(2^x)=2^{-2x}
The solution is x=0