What is the answer to 4^{5x+1}+7=28 ?

The answer to 4^{5x+1}+7=28 is x=(ln(21)-2ln(2))/(10ln(2))

Solve for x: 4^{5x+1}+7=28

The solution is x=(ln(21)-2ln(2))/(10ln(2))

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4^{5 x + 1} + 7 = 28

x = \frac{ln ( 21 ) - 2 ln ( 2 )}{10 ln ( 2 )}

Decimal Notation

x = 0.23923 \dots

Solution steps

4^{5 x + 1} + 7 = 28

Move

7

to the right side

4^{5 x + 1} = 21

Apply exponent rules

(5 x + 1) ln (4) = ln (21)

Solve

(5 x + 1) ln (4) = ln (21) : x = \frac{ln ( 21 ) - 2 ln ( 2 )}{10 ln ( 2 )}

x = \frac{ln ( 21 ) - 2 ln ( 2 )}{10 ln ( 2 )}

2^{- x} = 5

(e^{4})^{x} (e^{x})^{2} = e^{1} 2

5^{2 x - 1} = 5

3^{x - 2} = 9

6 4^{x} = 16

What is the answer to 4^{5x+1}+7=28 ?
The answer to 4^{5x+1}+7=28 is x=(ln(21)-2ln(2))/(10ln(2))
Solve for x: 4^{5x+1}+7=28
The solution is x=(ln(21)-2ln(2))/(10ln(2))