What is the answer to 3^x=2*(5^x) ?

The answer to 3^x=2*(5^x) is x=(ln(2))/(ln(3)-ln(5))

Solve for x: 3^x=2*(5^x)

The solution is x=(ln(2))/(ln(3)-ln(5))

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3^{x} = 2 \cdot (5^{x})

x = \frac{ln ( 2 )}{ln ( 3 ) - ln ( 5 )}

Decimal Notation

x = - 1.35691 \dots

Solution steps

3^{x} = 2 (5^{x})

Apply exponent rules

x ln (3) = ln (2) + x ln (5)

Solve

x ln (3) = ln (2) + x ln (5) : x = \frac{ln ( 2 )}{ln ( 3 ) - ln ( 5 )}

x = \frac{ln ( 2 )}{ln ( 3 ) - ln ( 5 )}

2^{a^{2}} = 8^{a} \cdot 16

2 \cdot 3^{x} = 6^{x}

e^{1 - 2 x} = \frac{1}{e ^{3 x + 3}}

1 0^{x} = 7.21

20000 = 10000 (1 + 0.15)^{t}

What is the answer to 3^x=2*(5^x) ?
The answer to 3^x=2*(5^x) is x=(ln(2))/(ln(3)-ln(5))
Solve for x: 3^x=2*(5^x)
The solution is x=(ln(2))/(ln(3)-ln(5))