What is the answer to 4*2^{5x}=21 ?

The answer to 4*2^{5x}=21 is x=(ln(21/4))/(5ln(2))

Solve for x: 4*2^{5x}=21

The solution is x=(ln(21/4))/(5ln(2))

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4 \cdot 2^{5 x} = 21

x = \frac{ln ( \frac{21}{4} )}{5 ln ( 2 )}

Solution steps

4 \cdot 2^{5 x} = 21

Divide both sides by

4

2^{5 x} = \frac{21}{4}

Apply exponent rules

5 x ln (2) = ln (\frac{21}{4})

Solve

5 x ln (2) = ln (\frac{21}{4}) : x = \frac{ln ( \frac{21}{4} )}{5 ln ( 2 )}

x = \frac{ln ( \frac{21}{4} )}{5 ln ( 2 )}

5 (2^{3 x}) = 8

2^{3 x + 1} - 2^{2 x - 1} = 2^{x + 3} - 2

2^{5 x - 2} = 2^{x}

x, e^{x - 3} = 2

(\frac{2}{3})^{x} = 5^{x - 1}

What is the answer to 4*2^{5x}=21 ?
The answer to 4*2^{5x}=21 is x=(ln(21/4))/(5ln(2))
Solve for x: 4*2^{5x}=21
The solution is x=(ln(21/4))/(5ln(2))