What is the answer to 10^x=31 ?

The answer to 10^x=31 is x=(ln(31))/(ln(10))

The solution is x=(ln(31))/(ln(10))

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10^x=31

1 0^{x} = 31

x = \frac{ln ( 31 )}{ln ( 10 )}

Decimal Notation

x = 1.49136 \dots

Solution steps

1 0^{x} = 31

Apply exponent rules

x ln (10) = ln (31)

Solve

x ln (10) = ln (31) : x = \frac{ln ( 31 )}{ln ( 10 )}

x = \frac{ln ( 31 )}{ln ( 10 )}

1 0^{x} = 87

2 5^{3 x + 2} = 125

3^{x} + 5 \cdot 3^{x} = 54

x^{2} 1 0^{x} - x 1 0^{x} = 2 (1 0^{x})

x, 3^{x} = 5