What is the answer to \sqrt[x+2]{8}=\sqrt[x-4]{32} ?

The answer to \sqrt[x+2]{8}=\sqrt[x-4]{32} is x=-11

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\sqrt[x+2]{8}=\sqrt[x-4]{32}

x = - 11

Solution steps

Apply exponent rules

\frac{3}{x + 2} = \frac{5}{x - 4}

Solve

\frac{3}{x + 2} = \frac{5}{x - 4} : x = - 11

x = - 11

5^{x + 1} = 7^{x - 1}

9^{x} - 4 \cdot 3^{x + 1} + 27 = 0

5^{x^{2} - 12} = 2 5^{2 x}

2 x^{- 3} e^{5 l n (x)} - x - 3 = 0

2^{x + 2} - 2^{x} = 96

What is the answer to \sqrt[x+2]{8}=\sqrt[x-4]{32} ?
The answer to \sqrt[x+2]{8}=\sqrt[x-4]{32} is x=-11
Solve for x: \sqrt[x+2]{8}=\sqrt[x-4]{32}
The solution is x=-11