What is the answer to 8^{x^2-x}=4^{x+1} ?

The answer to 8^{x^2-x}=4^{x+1} is x=2,x=-1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8^{x^2-x}=4^{x+1}

8^{x^{2} - x} = 4^{x + 1}

x = 2, x = - \frac{1}{3}

Decimal Notation

x = 2, x = - 0.33333 \dots

Solution steps

8^{x^{2} - x} = 4^{x + 1}

Apply exponent rules

3 (x^{2} - x) = 2 (x + 1)

Solve

3 (x^{2} - x) = 2 (x + 1) : x = 2, x = - \frac{1}{3}

x = 2, x = - \frac{1}{3}

e^{2 x} = \frac{1}{8}

m e^{m x} + 2 e^{m x} = 0

(100)^{x} = 0

8 1^{x} = 9

e^{2 z - 1} = 1

What is the answer to 8^{x^2-x}=4^{x+1} ?
The answer to 8^{x^2-x}=4^{x+1} is x=2,x=-1/3
Solve for x: 8^{x^2-x}=4^{x+1}
The solution is x=2,x=-1/3