What is the answer to 7^{x-2}=5^x ?

The answer to 7^{x-2}=5^x is x=(2ln(7))/(ln(7)-ln(5))

Solve for x: 7^{x-2}=5^x

The solution is x=(2ln(7))/(ln(7)-ln(5))

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7^{x - 2} = 5^{x}

x = \frac{2 ln ( 7 )}{ln ( 7 ) - ln ( 5 )}

Decimal Notation

x = 11.56654 \dots

Solution steps

7^{x - 2} = 5^{x}

Apply exponent rules

(x - 2) ln (7) = x ln (5)

Solve

(x - 2) ln (7) = x ln (5) : x = \frac{2 ln ( 7 )}{ln ( 7 ) - ln ( 5 )}

x = \frac{2 ln ( 7 )}{ln ( 7 ) - ln ( 5 )}

12 5^{x} = 0.04

3^{5 x - 1} = 81

6^{x} = \frac{1}{216}

- x^{2} e^{- x} = 2 x e^{- x}

6^{2 x + 5} - 36 = 0

What is the answer to 7^{x-2}=5^x ?
The answer to 7^{x-2}=5^x is x=(2ln(7))/(ln(7)-ln(5))
Solve for x: 7^{x-2}=5^x
The solution is x=(2ln(7))/(ln(7)-ln(5))