What is the answer to 4^{x+1}= 1/(8sqrt(2)) ?

The answer to 4^{x+1}= 1/(8sqrt(2)) is x=-11/4

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4^{x+1}= 1/(8sqrt(2))

4^{x + 1} = \frac{1}{8 2}

x = - \frac{11}{4}

Decimal Notation

x = - 2.75

Solution steps

4^{x + 1} = \frac{1}{8 2}

Apply exponent rules

2 (x + 1) = - \frac{7}{2}

Solve

2 (x + 1) = - \frac{7}{2} : x = - \frac{11}{4}

x = - \frac{11}{4}

5^{3 x + 4} = 45

2 \cdot 5^{x + 1} = 250

4^{9 x + 4} = 3

3^{2 x - 1} = 4 \cdot 3^{x - 1} - 1

y, e^{- e^{- y}} = 1 - 0.05

What is the answer to 4^{x+1}= 1/(8sqrt(2)) ?
The answer to 4^{x+1}= 1/(8sqrt(2)) is x=-11/4
Solve for x: 4^{x+1}= 1/(8sqrt(2))
The solution is x=-11/4