What is the answer to 8^{x-1}=16^{3x} ?

The answer to 8^{x-1}=16^{3x} is x=-1/3

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8^{x-1}=16^{3x}

8^{x - 1} = 1 6^{3 x}

x = - \frac{1}{3}

Decimal

x = - 0.33333 \dots

Solution steps

8^{x - 1} = 1 6^{3 x}

Apply exponent rules

3 (x - 1) = 12 x

Solve

3 (x - 1) = 12 x : x = - \frac{1}{3}

x = - \frac{1}{3}

0.5 = 2^{x}

15 = 286.93 (0.973 8^{x})

lo g_{5} (3^{2 x}) = 7

18 = 4 + e^{20 \cdot k} \cdot 21

e^{z} = - 2