What is the answer to 3^{x+4}=2^{x-16} ?

The answer to 3^{x+4}=2^{x-16} is x=(-16ln(2)-4ln(3))/(ln(3)-ln(2))

Solve for x: 3^{x+4}=2^{x-16}

The solution is x=(-16ln(2)-4ln(3))/(ln(3)-ln(2))

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3^{x + 4} = 2^{x - 16}

x = \frac{- 16 ln ( 2 ) - 4 ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

Decimal Notation

x = - 38.19022 \dots

Solution steps

3^{x + 4} = 2^{x - 16}

Apply exponent rules

(x + 4) ln (3) = (x - 16) ln (2)

Solve

(x + 4) ln (3) = (x - 16) ln (2) : x = \frac{- 16 ln ( 2 ) - 4 ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

x = \frac{- 16 ln ( 2 ) - 4 ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

t, 2 a^{\frac{t}{3}} = 5

5^{x + 5} = 1

8 1^{x} = 2 7^{x + 2}

2^{2 x} = 32

1 0^{4 x} = 20

What is the answer to 3^{x+4}=2^{x-16} ?
The answer to 3^{x+4}=2^{x-16} is x=(-16ln(2)-4ln(3))/(ln(3)-ln(2))
Solve for x: 3^{x+4}=2^{x-16}
The solution is x=(-16ln(2)-4ln(3))/(ln(3)-ln(2))