What is the answer to 5^{x-7}=11^{x-7} ?

The answer to 5^{x-7}=11^{x-7} is x=(7ln(11)-7ln(5))/(ln(11)-ln(5))

Solve for x: 5^{x-7}=11^{x-7}

The solution is x=(7ln(11)-7ln(5))/(ln(11)-ln(5))

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5^{x - 7} = 1 1^{x - 7}

x = \frac{7 ln ( 11 ) - 7 ln ( 5 )}{ln ( 11 ) - ln ( 5 )}

Decimal Notation

x = 7

Solution steps

5^{x - 7} = 1 1^{x - 7}

Apply exponent rules

(x - 7) ln (5) = (x - 7) ln (11)

Solve

(x - 7) ln (5) = (x - 7) ln (11) : x = \frac{7 ln ( 11 ) - 7 ln ( 5 )}{ln ( 11 ) - ln ( 5 )}

x = \frac{7 ln ( 11 ) - 7 ln ( 5 )}{ln ( 11 ) - ln ( 5 )}

e^{x} = x - 2

x, ln (y) = e^{x}

5^{x} \cdot 3^{x} = 3375

2 e^{x} = 0

What is the answer to 5^{x-7}=11^{x-7} ?
The answer to 5^{x-7}=11^{x-7} is x=(7ln(11)-7ln(5))/(ln(11)-ln(5))
Solve for x: 5^{x-7}=11^{x-7}
The solution is x=(7ln(11)-7ln(5))/(ln(11)-ln(5))