What is the answer to 2^{(1-x^2)}= 1/8 ?

The answer to 2^{(1-x^2)}= 1/8 is x=2,x=-2

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2^{(1-x^2)}= 1/8

2^{(1 - x^{2})} = \frac{1}{8}

x = 2, x = - 2

Solution steps

2^{(1 - x^{2})} = \frac{1}{8}

Apply exponent rules

1 - x^{2} = - 3

Solve

1 - x^{2} = - 3 : x = 2, x = - 2

x = 2, x = - 2

2^{x + 1} = 4

1 6^{x} = 0.5

e^{x} = e

4^{x} = 3^{x + 1}

(\frac{1}{8})^{- 3 a} = 51 2^{3 a}

What is the answer to 2^{(1-x^2)}= 1/8 ?
The answer to 2^{(1-x^2)}= 1/8 is x=2,x=-2
Solve for x: 2^{(1-x^2)}= 1/8
The solution is x=2,x=-2