What is the answer to 5^{2x-3}=7^{x+1} ?

The answer to 5^{2x-3}=7^{x+1} is x=(ln(875))/(2ln(5)-ln(7))

Solve for x: 5^{2x-3}=7^{x+1}

The solution is x=(ln(875))/(2ln(5)-ln(7))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5^{2 x - 3} = 7^{x + 1}

x = \frac{ln ( 875 )}{2 ln ( 5 ) - ln ( 7 )}

Decimal Notation

x = 5.32160 \dots

Solution steps

5^{2 x - 3} = 7^{x + 1}

Apply exponent rules

(2 x - 3) ln (5) = (x + 1) ln (7)

Solve

(2 x - 3) ln (5) = (x + 1) ln (7) : x = \frac{ln ( 875 )}{2 ln ( 5 ) - ln ( 7 )}

x = \frac{ln ( 875 )}{2 ln ( 5 ) - ln ( 7 )}

21 6^{x + 2} = 7776

4^{x} + 5 = 8

1 - e^{1 - x^{2}} = 0

9^{x} = 6561

5^{2 x} = 13

What is the answer to 5^{2x-3}=7^{x+1} ?
The answer to 5^{2x-3}=7^{x+1} is x=(ln(875))/(2ln(5)-ln(7))
Solve for x: 5^{2x-3}=7^{x+1}
The solution is x=(ln(875))/(2ln(5)-ln(7))