What is the answer to 3^{2x-1}-3^{x+1}=0 ?

The answer to 3^{2x-1}-3^{x+1}=0 is x=2

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3^{2x-1}-3^{x+1}=0

3^{2 x - 1} - 3^{x + 1} = 0

x = 2

Solution steps

3^{2 x - 1} - 3^{x + 1} = 0

Add

3^{x + 1}

to both sides

3^{2 x - 1} - 3^{x + 1} + 3^{x + 1} = 0 + 3^{x + 1}

Simplify

3^{2 x - 1} = 3^{x + 1}

Apply exponent rules

2 x - 1 = x + 1

Solve

2 x - 1 = x + 1 : x = 2

x = 2

4^{x} - 6 (2^{x}) - 16 = 0

a, x^{a + b} = x^{a} + x^{b}

4 (4^{2 x}) - 17 (4^{x}) + 4 = 0

2^{2 x + 3} - 8 \cdot 2^{x + 1} + 8 = 0

2^{2 x - 5} = 8

What is the answer to 3^{2x-1}-3^{x+1}=0 ?
The answer to 3^{2x-1}-3^{x+1}=0 is x=2
Solve for x: 3^{2x-1}-3^{x+1}=0
The solution is x=2