What is the answer to 25^{2x+2}=(1/5)^{5x-1} ?

The answer to 25^{2x+2}=(1/5)^{5x-1} is x=-1/3

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25^{2x+2}=(1/5)^{5x-1}

2 5^{2 x + 2} = (\frac{1}{5})^{5 x - 1}

x = - \frac{1}{3}

Decimal Notation

x = - 0.33333 \dots

Solution steps

2 5^{2 x + 2} = (\frac{1}{5})^{5 x - 1}

Apply exponent rules

2 (2 x + 2) = - (5 x - 1)

Solve

2 (2 x + 2) = - (5 x - 1) : x = - \frac{1}{3}

x = - \frac{1}{3}

4^{- 2 m - 1} = 4^{2 m}

e^{x + 1} = e^{2 - x}

z, 3^{x} = 4^{y} = 1 2^{z}

2^{2 x - 1} - 9 \cdot 2^{x - 2} + 1 = 0

e^{2 x} + 3 e^{x} = 10

What is the answer to 25^{2x+2}=(1/5)^{5x-1} ?
The answer to 25^{2x+2}=(1/5)^{5x-1} is x=-1/3
Solve for x: 25^{2x+2}=(1/5)^{5x-1}
The solution is x=-1/3