What is the answer to 10^{x+2}-12=22 ?

The answer to 10^{x+2}-12=22 is x=(ln(34))/(ln(10))-2

Solve for x: 10^{x+2}-12=22

The solution is x=(ln(34))/(ln(10))-2

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1 0^{x + 2} - 12 = 22

x = \frac{ln ( 34 )}{ln ( 10 )} - 2

Decimal Notation

x = - 0.46852 \dots

Solution steps

1 0^{x + 2} - 12 = 22

Move

12

to the right side

1 0^{x + 2} = 34

Apply exponent rules

(x + 2) ln (10) = ln (34)

Solve

(x + 2) ln (10) = ln (34) : x = \frac{ln ( 34 )}{ln ( 10 )} - 2

x = \frac{ln ( 34 )}{ln ( 10 )} - 2

2^{x} = A^{\frac{x}{12}}

86 \cdot 1 0^{\frac{x}{4}} = 41

8^{x + 6} = 5^{x}

\frac{16 e ^{4 x - 8}}{e ^{16} - 1} = 0

ln (e^{x}) = 2

What is the answer to 10^{x+2}-12=22 ?
The answer to 10^{x+2}-12=22 is x=(ln(34))/(ln(10))-2
Solve for x: 10^{x+2}-12=22
The solution is x=(ln(34))/(ln(10))-2