What is the answer to 81^{x^{2-1}}=27^{-(7-5x)} ?

The answer to 81^{x^{2-1}}=27^{-(7-5x)} is x= 21/11

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81^{x^{2-1}}=27^{-(7-5x)}

8 1^{x^{2 - 1}} = 2 7^{- (7 - 5 x)}

x = \frac{21}{11}

Decimal Notation

x = 1.90909 \dots

Solution steps

8 1^{x^{2 - 1}} = 2 7^{- (7 - 5 x)}

Apply exponent rules

4 x = - 3 (7 - 5 x)

Solve

4 x = - 3 (7 - 5 x) : x = \frac{21}{11}

x = \frac{21}{11}

2^{3 x - 1} = 8

2^{3 x - 1} = 4

1000000 = 2^{x}

12 \cdot 1 0^{\frac{x}{2}} = 1

3^{x + 2} = \frac{1}{9}

What is the answer to 81^{x^{2-1}}=27^{-(7-5x)} ?
The answer to 81^{x^{2-1}}=27^{-(7-5x)} is x= 21/11
Solve for x: 81^{x^{2-1}}=27^{-(7-5x)}
The solution is x= 21/11