What is the answer to (2^x-8)(2^x-1)=0 ?

The answer to (2^x-8)(2^x-1)=0 is x=3,x=0

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(2^x-8)(2^x-1)=0

(2^{x} - 8) (2^{x} - 1) = 0

x = 3, x = 0

Solution steps

(2^{x} - 8) (2^{x} - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2^{x} - 8 = 0 or 2^{x} - 1 = 0

Solve

2^{x} - 8 = 0 : x = 3

Solve

2^{x} - 1 = 0 : x = 0

x = 3, x = 0

e^{5 x - 1} = 26

2^{2 - x} - 4^{x} = - 15

5^{3 x - 2} = 12 5^{2 x}

e^{y} = 8

x, 2^{x - 5} = 3

What is the answer to (2^x-8)(2^x-1)=0 ?
The answer to (2^x-8)(2^x-1)=0 is x=3,x=0
Solve for x: (2^x-8)(2^x-1)=0
The solution is x=3,x=0