What are the solutions to the equation 3x^2=16-8x ?

The solutions to the equation 3x^2=16-8x are x= 4/3 ,x=-4

Find the zeros of 3x^2=16-8x

The zeros of 3x^2=16-8x are x= 4/3 ,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} = 16 - 8 x

x = \frac{4}{3}, x = - 4

Solution steps

3 x^{2} = 16 - 8 x

Move

8 x

to the left side

3 x^{2} + 8 x = 16

Move

16

to the left side

3 x^{2} + 8 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 16 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 16) = 16

x_{1, 2} = \frac{- 8 \pm 16}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 16}{2 \cdot 3}, x_{2} = \frac{- 8 - 16}{2 \cdot 3}

x = \frac{- 8 + 16}{2 \cdot 3} : \frac{4}{3}

x = \frac{- 8 - 16}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 4

lo g_{3} (0.2)

37.7 = 2 π r

3 - 2 x > 7

\frac{2 x - 3}{5} + 1 = 4 x + 4

\frac{- ( - 2 )}{2 ( 1 )}

What are the solutions to the equation 3x^2=16-8x ?
The solutions to the equation 3x^2=16-8x are x= 4/3 ,x=-4
Find the zeros of 3x^2=16-8x
The zeros of 3x^2=16-8x are x= 4/3 ,x=-4