What is the answer to solvefor x,z=6e^{x^2y^3} ?

The answer to solvefor x,z=6e^{x^2y^3} is x=sqrt((ln(z/6))/(y^3)),x=-sqrt((ln(z/6))/(y^3))

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solvefor x,z=6e^{x^2y^3}

solve for

x, z = 6 e^{x^{2} y^{3}}

x = \frac{ln ( \frac{z}{6} )}{y ^{3}}, x = - \frac{ln ( \frac{z}{6} )}{y ^{3}}

Solution steps

z = 6 e^{x^{2} y^{3}}

Switch sides

6 e^{x^{2} y^{3}} = z

Divide both sides by

6

e^{x^{2} y^{3}} = \frac{z}{6}

Apply exponent rules

x^{2} y^{3} = ln (\frac{z}{6})

Solve

x^{2} y^{3} = ln (\frac{z}{6}) : x = \frac{ln ( \frac{z}{6} )}{y ^{3}}, x = - \frac{ln ( \frac{z}{6} )}{y ^{3}}

x = \frac{ln ( \frac{z}{6} )}{y ^{3}}, x = - \frac{ln ( \frac{z}{6} )}{y ^{3}}

32 = 8^{f + 3}

5^{3 b - 1} = 5^{b - 3}

4^{3 x} = 8^{x + 5}

4^{x} = 40

4^{x} = 13

What is the answer to solvefor x,z=6e^{x^2y^3} ?
The answer to solvefor x,z=6e^{x^2y^3} is x=sqrt((ln(z/6))/(y^3)),x=-sqrt((ln(z/6))/(y^3))