What is the answer to 7^{x+2}=17 ?

The answer to 7^{x+2}=17 is x=(ln(17))/(ln(7))-2

Solve for x: 7^{x+2}=17

The solution is x=(ln(17))/(ln(7))-2

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7^{x + 2} = 17

x = \frac{ln ( 17 )}{ln ( 7 )} - 2

Decimal Notation

x = - 0.54401 \dots

Solution steps

7^{x + 2} = 17

Apply exponent rules

(x + 2) ln (7) = ln (17)

Solve

(x + 2) ln (7) = ln (17) : x = \frac{ln ( 17 )}{ln ( 7 )} - 2

x = \frac{ln ( 17 )}{ln ( 7 )} - 2

(3^{x})^{2} - 3^{x + 1} + 2 = 0

2^{y} = 24

3^{x^{2}} - 9^{6 - 2 x} = 0

e^{3 l n (x)} = 125

5^{3 x - 3} = 1

What is the answer to 7^{x+2}=17 ?
The answer to 7^{x+2}=17 is x=(ln(17))/(ln(7))-2
Solve for x: 7^{x+2}=17
The solution is x=(ln(17))/(ln(7))-2