What is the answer to (4^{3-x})^{2-x}=1 ?

The answer to (4^{3-x})^{2-x}=1 is x=2,x=3

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(4^{3-x})^{2-x}=1

(4^{3 - x})^{2 - x} = 1

x = 2, x = 3

Solution steps

(4^{3 - x})^{2 - x} = 1

Apply exponent rules

(2 - x) ln (4^{3 - x}) = ln (1)

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 - x = 0 or ln (4^{3 - x}) = 0

Solve

2 - x = 0 : x = 2

Solve

ln (4^{3 - x}) = 0 : x = 3

x = 2, x = 3

4 e^{- 3 x} = 2

e^{x} = e^{x^{2} - 12}

1 + e^{\frac{1}{x}} = 0

9^{2 - x} = 2 7^{2 x + 1}

2 7^{a} = 243

What is the answer to (4^{3-x})^{2-x}=1 ?
The answer to (4^{3-x})^{2-x}=1 is x=2,x=3
Solve for x: (4^{3-x})^{2-x}=1
The solution is x=2,x=3