What is the answer to 3(2^{x+4})=228 ?

The answer to 3(2^{x+4})=228 is x=(ln(76))/(ln(2))-4

Solve for x: 3(2^{x+4})=228

The solution is x=(ln(76))/(ln(2))-4

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3 (2^{x + 4}) = 228

x = \frac{ln ( 76 )}{ln ( 2 )} - 4

Decimal Notation

x = 2.24792 \dots

Solution steps

3 (2^{x + 4}) = 228

Divide both sides by

3

2^{x + 4} = 76

Apply exponent rules

(x + 4) ln (2) = ln (76)

Solve

(x + 4) ln (2) = ln (76) : x = \frac{ln ( 76 )}{ln ( 2 )} - 4

x = \frac{ln ( 76 )}{ln ( 2 )} - 4

2^{5 x + 15} = 3 2^{x + 3}

x^{1 + l o g_{10} (x)} = 100

7^{x} = 8^{x}

2 = (1.05)^{x}

2 \cdot 9^{x - 4} + 12 = 66

What is the answer to 3(2^{x+4})=228 ?
The answer to 3(2^{x+4})=228 is x=(ln(76))/(ln(2))-4
Solve for x: 3(2^{x+4})=228
The solution is x=(ln(76))/(ln(2))-4