What is the answer to 3^{2x-3}=27^{(x+1)/2} ?

The answer to 3^{2x-3}=27^{(x+1)/2} is x=9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{2x-3}=27^{(x+1)/2}

3^{2 x - 3} = 2 7^{\frac{x + 1}{2}}

x = 9

Solution steps

3^{2 x - 3} = 2 7^{\frac{x + 1}{2}}

Apply exponent rules

2 x - 3 = \frac{3 ( x + 1 )}{2}

Solve

2 x - 3 = \frac{3 ( x + 1 )}{2} : x = 9

x = 9

e^{5 - 4 x} = 3

2401 = 7^{6 - 2 x}

5^{x + 1} - 5^{x} = 20

e^{3 - 4 x} = 2

What is the answer to 3^{2x-3}=27^{(x+1)/2} ?
The answer to 3^{2x-3}=27^{(x+1)/2} is x=9
Solve for x: 3^{2x-3}=27^{(x+1)/2}
The solution is x=9