What is the answer to 8(2^{2x})-10(2^x)+2=0 ?

The answer to 8(2^{2x})-10(2^x)+2=0 is x=0,x=-2

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8(2^{2x})-10(2^x)+2=0

8 (2^{2 x}) - 10 (2^{x}) + 2 = 0

x = 0, x = - 2

Solution steps

8 (2^{2 x}) - 10 (2^{x}) + 2 = 0

Apply exponent rules

8 (2^{x})^{2} - 10 \cdot 2^{x} + 2 = 0

Rewrite the equation with

2^{x} = u

8 (u)^{2} - 10 u + 2 = 0

Solve

8 u^{2} - 10 u + 2 = 0 : u = 1, u = \frac{1}{4}

u = 1, u = \frac{1}{4}

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 1 : x = 0

Solve

2^{x} = \frac{1}{4} : x = - 2

x = 0, x = - 2

(2)^{x} = 4^{x^{2} + 1}

2^{2 x} + 2^{x + 2} - 12 = 0

- x e^{- x} + e^{- x} = 0

x^{x} = 2^{1000000}

216 = (\frac{1}{36})^{x - 1}

What is the answer to 8(2^{2x})-10(2^x)+2=0 ?
The answer to 8(2^{2x})-10(2^x)+2=0 is x=0,x=-2
Solve for x: 8(2^{2x})-10(2^x)+2=0
The solution is x=0,x=-2