What is the answer to 6*3^{x-1}=6^{2x} ?

The answer to 6*3^{x-1}=6^{2x} is x=(ln(2))/(ln(12))

Solve for x: 6*3^{x-1}=6^{2x}

The solution is x=(ln(2))/(ln(12))

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6 \cdot 3^{x - 1} = 6^{2 x}

x = \frac{ln ( 2 )}{ln ( 12 )}

Decimal Notation

x = 0.27894 \dots

Solution steps

6 \cdot 3^{x - 1} = 6^{2 x}

Apply exponent rules

ln (6) + (x - 1) ln (3) = 2 x ln (6)

Solve

ln (6) + (x - 1) ln (3) = 2 x ln (6) : x = \frac{ln ( 2 )}{ln ( 12 )}

x = \frac{ln ( 2 )}{ln ( 12 )}

9^{x + 3} = 30

(\frac{1}{2})^{x^{2} - 3} = 4

7 - 3 e^{- x} = 2

y, (3^{3})^{- 1} = x^{y}

6 \cdot e^{0.25 t} = 9

What is the answer to 6*3^{x-1}=6^{2x} ?
The answer to 6*3^{x-1}=6^{2x} is x=(ln(2))/(ln(12))
Solve for x: 6*3^{x-1}=6^{2x}
The solution is x=(ln(2))/(ln(12))